Answer:
Area of the Irregular polygon is 26 square unit.
Explanation:
Given:
A figure of irregular polygon.
We need to find the are of the irregular figure.
We divide the irregular polygon in to rectangles.
Figure is attached with marking.
AG = 4 unit
AD = CB = 2 units
DF = AG - AD = 4 - 2 = 2 units
Area of the Polygon = Area of rectangle ABCD + Area of rectangle DEFG
= AB × CB + FG × DF
= 4 × 2 + 9 × 2
= 8 + 18
= 26 unit²
Therefore, Area of the Irregular polygon is 26 square unit.