Question

An electron traverses a vacuum tube with a length of 2 m in 2 X 10- 4

sec. What is the average speed of the
electron during this time?

Answer 1

`v=10^4\ m/s`

Step-by-step explanation:

Given that,

The length of a vacuum tube, d = 2 m

Time,
`t=2* 10^(-4)\ s`

We need to find the average speed of the electron during this time. Average speed is equal to total distance covered divided by total time taken.

Here, total distance = length of the vacuum tube

`v=(2)/(2* 10^(-4))\\\\=10^4\ m/s`

So, the average speed of the electron is
`10^4\ m/s`.