Question

A balloon that had a volume of 3.5 L at 25.0 C is placed in a hot room at 40.9 C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the room?

Answer 1

V1/T1 = V2/T2

V1= 3.5 L

T1 = 25 +273=298 K

T2 = 40.9 + 273 = 313.9 K

V2- ?

3.5 L/298 K= V2/ 313.9 K

V2 = (3.5 L*313.9 K)/298 K ≈ 3.69 L