146k views
5 votes
Let f(x) = x + |2x − 1|. find all solutions to the equation f(x) = 8. (enter your answers as a comma-separated list. if an answer does not exist, enter dne.)

User SChang
by
5.7k points

1 Answer

5 votes

Hi !



f(x) = x + |2x − 1|



We have the function at hand,so if the function is equal to 8,then x + |2x − 1| is equal to 8 too :



x + |2x − 1| = 8


Now we can express the module so:

|2x − 1| = 8-x


It means we'll have 2 options :


I : 2x-1 = 8-x


II : 2x-2 = -(8-x)



I : 2x-1 = 8-x | +x


2x-1+x = 8-x+x



3x-1 = 8 | + 1



3x-1+1 = 8+1



3x = 9 | ÷ 3



x = 3



II : 2x-1 = -(8-x)


2x-1 = -8+x | -x



2x-x-1 = -8+x-x


x-1 = -8 | +1



x-1+1 = -8+1



x = -7




Solutions : 3,-7

User Mark Lakewood
by
6.0k points