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Prove that the sum of five consecutive natural numbers is even​

User Nagaraju V
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Answer:

Conversely, if n is divisible by 5, then n is the sum of five consecutive integers. In particular, this gives n = 5m + 10 = 5(m + 2) and, since m + 2 is an integer, this shows n is divisible by 5

Explanation:

User Rodrigo Lira
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