Question

What volume of a 2.75 m solution of naoh is required to make 500.0 ml of a 1.27 m solution of naoh?

Answer 1

`V_1=230.9mL`

Step-by-step explanation:

Hello,

This is about a dilution exercise which could be mathematically solved by taking into account that during the dilution process the moles are conserved:

`n_1=n_2`

Now, as the moles could be expressed in term of molarity an volume one defines:

`M_1V_1=M_2V_2`

Then, we're asked to report
`V_1` as it is the volume we need to take from the inital 2.75M solution of NaOH, thus:

`V_1=(M_2V_2)/(M_1) =(1.27M*500.0mL)/(2.75M)\\V_1=230.9mL`

Best regards.

Answer 2

The volume of 2.75 M solution of NaOH required to make 500.0 ml of a 1.27M solution of NaOH is 230.9 Ml

calculation

by use of M1V1=M2V2 volume formula where

M1=2.75 m

V1=?

M2= 500 Ml

V2= 1.27 M

make V1 the subject of the formula V1= M2V2/M1

V1 is therefore= 500Ml x 1.27 M/ 2.75 M = 230.9 Ml