Question

Which statement best describes the offspring of the F1 generation when crossing a pea plant that is true breeding for green seeds with a pea plant that is true breeding for yellow seeds?

a) the green trait is the dominant trait

b) the offspring will inherit one gene from each parent

c) the offspring will have both green and yellow seeds

d) each offspring will have a unique set of alleles

Answer 1

This question is missing some key information, which will be assumed below:

A Punnett Square between true bred-green and true-bred yellow plants:

G G

Y YG YG

Y YG YG

which means that all offsprings of the G1 generation are heterozygous yellow (dominant) seeds.

This means

1. All offsprings have yellow seeds, so yellow is the dominant trait.

2. All offsprings inherit one allele from each parent, since both parents are true-bred (homozygous).

3. All offsprings have only yellow (dominant) seeds, because

4. All offsprings have the same combination of alleles, namely heterozygous for the green/yellow alleles.

Answer 2

b) the offspring will inherit one gene from each parent

Step-by-step explanation:

A true breeding plant is the one that produces offspring of the same phenotype upon self-fertilization.

Therefore if the gene for yellow seed is represented as y and for green seed as Y, then a true breeding green plant will have the genotype YY and yellow plant will have the genotype yy.

Now if you cross them, YY X yy ----> Yy

The offspring will inherit one gene from each of its parents, that is Y from the green seed parent and y from the yellow seed plant.