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Compound events help!!!!

Compound events help!!!!-example-1
User Statwonk
by
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1 Answer

5 votes

Let
M,F,P denote the events that a student is male, a student is female, and a student has a phone, respectively. Then we're given



P(M)=(420)/(800)



P(F)=1-P(M)=(380)/(800)



P(P)=(325)/(800)


We want to determine
P(M\cup P), which is equivalent to



P(M\cup P)=P(M)+P(P)-P(M\cap P)


By the law of total probability, we have



P(P)=P(M\cap P)+P(F\cap P)


That is, any student belonging to
P will be either male or female, and the events
M and
F are mutually exclusive of one another (because they are complementary). We're told that



P(F\mid P)=(200)/(325)


By definition of conditional probability,



P(F\mid P)=(P(F\cap P))/(P(P))=(P(F\cap P))/((325)/(800))\implies P(F\cap P)=(200)/(800)


and so



P(P)=P(M\cap P)+P(F\cap P)\iff(325)/(800)=P(M\cap P)+(200)/(800)\implies P(M\cap P)=(125)/(800)


So we have



P(M\cup P)=(420)/(800)+(325)/(800)-(125)/(800)=(620)/(800)

User Charles Ritchie
by
6.4k points
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