Question

3. Suppose an electric field with a magnitude of 2.8 E 4 N/C at a certain location, points due south. If a charge of -4.0 E -6 C is brought to the location, what is the electrostatic force that acts on this charge?

Answer 1

Force on the charge=0.112 N

Step-by-step explanation:

The force is given by

F= q E

q= charge=-4 x 10⁻⁶ C

E= electric field= 2.8 x 10⁴ N/C

F=(-4 x 10⁻⁶) (2.8 x 10⁴)

F=0.112 N