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Working​ together, it takes two roofers 12 hours to put a new roof on a portable classroom. if the first roofer can do the job by himself in 16 ​hours, how many hours will it take the second roofer to do the job by​ himself?

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Let r and s be the respective rates in roofs per hour.



12 = 1/(r+s)



r+s=1/12



s= -r + \frac 1 {12}



16=1/r



r=1/16



s= - \frac 1{16} + \frac 1 {12}[tex] = -(3)/(48) + (4)/(48) = (1)/(48)


The second worker's rate is 1/48 roofs per hour or one roof every 48 hours.




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