Question

Find the solution to the systems of equations using the elimination method.

2x + 3y = 11
5x + 3y = 14

Answer 1

X=-2/3y+11/3

x=-3/5y+14/5

Answer 2

x = 1 ; y = 3

Explanation:

5(2x + 3y = 11)

2(5x + 3y + 14)

(distribute)

10x + 15y = 55

10x + 6y = 28

(subtract)

9y = 27

(divided 9 to both sides)

9 divided by 9 cancels out and 27 divided by 9 = 3

so..

y = 3

now, using any equation, (i’ll be using 2x + 3y =11) plug in the y value to find the x value

2x + 3y = 11

2x + 3(3) = 11

(multiply 3 x 3)

2x + 9 = 11

(subtract 9 from 9 and 11)

2x = 2

(divide 2 from both sides)

2 divided by 2 = 1

therefore...

x = 1