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The variable z has a standard normal distribution. find the value z such that the event z > z has proportion 0.08. z = –1.41 z = 0.53 z = 0.82 z = 1.41

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The appropriate choice is z = 1.41.


The empirical rule tells you 68% of the distribution is within 1 standard deviation, so p(z > 1) ≈ 0.17. This means the z value is more than 1 for the probability to drop to 0.08. The only choice that is greater than 1 is 1.41. (The number is actually about 1.40507.)

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