Question

A bag contains 4 balls. Each ball is a single color, and 3 distinct colors are represented in the bag. What is the probability that the first 2 balls selected without replacement are the same color? Express your answer as a common fraction.

Answer 1

There are exactly ${4 \choose 2} = 6$ pairs of balls that we can choose. Since there are only 4 balls and 3 different colors, there is exactly one pair of same-colored balls. So, the probability of drawing this exact pair is $\boxed{\frac{1}{6}}$.

Answer: 1/6

Answer 2

The question here says there are 3 different colors and 1 of them has 2 balls. To select two same color balls we need to pick that particular ball.
The chance is:

`(2)/(4) * (1)/(3) = (1)/(6)`