So we can solve this using the Pythagorean theorem. The basic equation is as follows:
![a^(2) +b^(2)= c^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/xl43673z4rr6c1t08sc5qny01rqhhbbyt0.png)
where a and b are the values of the two legs of a right triangle, and c is the value of the hypotenuse.
So let's plug in the values given via the picture:
![14^(2)+ x^(2)= 17^(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/d9u1lastsd85g6qqktn2w3l71b67gv5k67.png)
And then we solve for x:
![196+x^(2) =289](https://img.qammunity.org/2019/formulas/mathematics/middle-school/9dxvodipggi549gkr8kdd5txjq5st0id1y.png)
![x^(2) =93](https://img.qammunity.org/2019/formulas/mathematics/middle-school/oqwvao7gqzeofenvs2egl6g017pwqx5xc9.png)
![x=√(93)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ty43kpbehb22ea0hw0d4v28f9y8p75b93r.png)
So now we know the value of x is the squareroot of 93.