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Identify the vertex and the y-intercept of the graph of the function y--(x+3 +4

User SanDash
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1 Answer

6 votes

The vertex is at (-3, 4)



This can be found by looking at the basic form of vertex form:



y = (x - h)^2 + k



In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = 4. This means the vertex is at (-3, 4).



The y-intercept is at 13. To find this we must first square the parenthesis and get the equation into standard form.


y = (x + 3)^2 + 4

y = x^2 + 6x + 9 + 4

y = x^2 + 6x + 13


Now we know that the y-intercept is equal to the constant, which is the last number in the equation.

User JHollanti
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