Answer:
The question is partially wrong. For spills of strong bases, such as sodium hydroxide, it must be neutralized with sulfuric or hydrochloric acid. Otherwise, for acid spills, neutralize them with sodium bicarbonate. The reactions are as follows:
Base spills: H2SO4 + 2NaOH → Na2SO4 + 2H2O
Sulfuric acid reacts with sodium hydroxide forming sodium sulfate and water.
Acid spills: H2SO4 + 2NaHCO3 → Na2SO4 + 2CO2 + 2H2O
Sulfuric acid reacts with sodium bicarbonate forming sodium sulfate, water and carbon dioxide.
Step-by-step explanation:
For the destruction of strong inorganic bases such as sodium hydroxide (NaOH) they must be neutralized with a dilute solution of sulfuric acid or a dilute solution of hydrochloric acid.
For the destruction of strong inorganic acids such as sulfuric acid, they must be neutralized with an inorganic base such as sodium bicarbonate (NaHCO3)