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What is the equilibrium constant expression for the ksp of sr3(po4)2?

2 Answers

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The equilibrium constant expression for KSP of Sr3(PO4)2 is


KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}


Explanation


write the ionic equation for Sr3(PO4)2


Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-


KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

User Ramson Tutte
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3 votes

The equilibrium constant expression for KSP of Sr3(PO4)2 is


KSP={(Sr^2+)^3 (PO4^3-)^2/ Sr3(PO4)2}


Explanation


write the ionic equation for Sr3(PO4)2


Sr3(PO4)2 → 3Sr^2+ + 2 PO4^3-


KSP is given by (concentration of the products raised to their coefficient /concentration of reactants raised to their coefficient)

User John Pasquet
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5.3k points