Question

Find the equation of the line in standard form with a point -3/3 and a slope of -4/3

Answer 1

Use the point-slope form of the equation of a line.


`y - y_1 = m(x - x_1)`


`y - 3 = -(4)/(3)[x - (-3)]`


`y - 3 = -(4)/(3)(x + 3)`


`3(y - 3) = -4(x + 3)`


`3y - 9 = -4x - 12`


`4x + 3y = -3`