Question

A gas that exerts a pressure of 6.20 atm in a container with a bolume of __ mL will exert a pressure of 9.150 atm when transferred to a container with a volume of 322 mL.

Answer 1

Answer:475 ml

Begin by writing down what you know

Use Boyle's Law (P1V1=P2V2)

Rearrange it for V1

V1=P2V2/P1

Plug in the numbers

Step-by-step explanation:

Answer 2

P1V1 = P2V2

P1 = 6.20 atm
V1 -?
P2= 9.150 atm
V2 = 322 mL

6.20 atm*V1 = 9.150 atm *322 mL

V1=9.150 atm *322 mL/6.20 atm ≈ 475 mL
V1 = 475 mL