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what is the equation of the line that is perpendicular to y=7/9x+15 and goes through the point (-1,2)
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what is the equation of the line that is perpendicular to y=7/9x+15 and goes through the point (-1,2)

User Sam Khan
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1 Answer

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y=7/9x+15 so slope = 7/9

perpendicular line, slope is opposite and reciprocal
so slope of of a line perpendicular to line = -9/7

passing point (-1,2)y - 2 = -9/7(x + 1)y - 2 = -9/7 x - 9/7

y = - 9/7 x + 5/7

Answery = - 9/7 x + 5/7
User Richard Kho
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