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*PLEASE help*
P(A)= 98%, find p(not A)

2 Answers

2 votes

P(A')=1-P(A)=100\%-98\%=2\%
User Pavel Vasilev
by
5.6k points
3 votes
Hi there!

Given P(A) = 98%

To find P(not A) we must first convert P(A) into a decimal. To find 98% as a decimal we only need to divide by 100.

98\% = 98 / 100 = 0.98

Now we know the following:
P(A) = 0.98. To find P(not A) we need to subtract P(A) from 1.

P(not A) =
1 - P(A)
P(not A) =
1 - 0.98 = 0.02

Change into a percentage by multiplying the decimal by 100.
P(not A) = P(A') =
0.02 * 100 = 2\%

Hope this helps you!
User Rheone
by
6.0k points