Question

PLZ ANSWER ASAP!!!!

Which statements are true about the graph of the function f(x) = 6x – 4 + x2? Check all that apply. The vertex form of the function is f(x) = (x – 2)2 + 2. The vertex of the function is (–3, –13). The axis of symmetry for the function is x = 3. The graph increases over the interval (–3, ). The function does not cross the x-axis.

Answer 1

`f(x) = 6x - 4 + x^2`

We complete the square to get vertex form.


`f(x) = x^2 + 6x - 4`


`f(x) = x^2 +6x + 9-9- 4`


`f(x) = (x+3)^2-13`

The vertex form of the function is f(x) = (x – 2)2 + 2.

Nope.

The vertex of the function is (–3, –13).

Yes, that's easily seen from the vertex form we got.

The axis of symmetry for the function is x = 3.

Nope, x = -3 is the symmetry axis.

The graph increases over the interval (–3, infinity).

That's true; the minimum is at the vertex when the squared term is zero and it increases both ways from there.

The function does not cross the x-axis.

No, it does cross; its minimum is -13 and it goes up from there.