So the equation for the volume of the sphere is
![V= (4)/(3) \pi r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/1ndsdkkz81yndefhd373yi5ut9c2z4opwo.png)
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For this, you'll need to plug in 128 pi into the volume placeholder and solve for r.
![128 \pi = (4)/(3) \pi r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/i2o84uwfl4y616tyqv2xucrcafrrmx0el9.png)
Firstly, divide by pi on each side of the equation to cancel out pi. Your equation will look like this:
![128=(4)/(3)r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/1sdk7ncwd61py53tispzaha4jm7y8wgc0e.png)
Next, you'll want to multiply 3/4 on each side to cancel out 4/3. Your equation will look like this:
![96=r^3](https://img.qammunity.org/2019/formulas/mathematics/high-school/wk5csmv561mjqhxxgh9ilzoogzpiktmz59.png)
Lastly, you'll want to 3rd root each side of the equation, and your answer should be
![4.58=r](https://img.qammunity.org/2019/formulas/mathematics/high-school/hnwjit3ok7nrjuegn4egx1pklfrgr2ky60.png)
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The correct option is B. 4.58