WHat are the solutions of x^2-5x+7=0

asked Nov 3, 2019 17.8k views

4 votes

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$x^2-5x+7=0\\a=1\ ;\ b=-5\ ;\ c=7\\\Delta=b^2-4ac\\\Delta=(-5)^2-4\cdot1\cdot7=25-28=-3\\\Delta\ \ \textless \ \ 0\\no\ solution$

Nzhenry answered Nov 5, 2019

7.4k points

1 vote

Answer:

x = 5+i√3/2 or x = 5-i√3/2

Explanation:

Yeah this equation makes no sense but the answer on A p e x that I got was that.

Pixelfreak answered Nov 7, 2019

7.7k points

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