Question

The decay of 601 mg of an isotope is described by the function A(t)= 601e-0.019t, where t is time in years. Find the amount left after 34 years. Round your answer to the nearest mg. Show all of your work for full credit. (5 points)

Answer 1

We already have the formula given to us. Now we just have to solve for the amount left after we sub in 34 for the t in the equation.
`A(t)=601(e^((-.019)(34)))` which simplifies to
`A(t)=601(e^(-.646))`. Raise e to that exponent to get A(t) = 601(.5241381418). Doing the multiplication we get that the amount left after 34 years is 315 mg