Question

A beetle crawls from x=1.09m to x=2.55m in 12.8s. what was the average velocity?

Answer 1

The average velocity of the beetle is equal to the ratio between the displacement and the time:

`v=(S)/(t)`

The displacement of the beetle is

`S=2.55 m-1.09 m=1.46 m`

The time is t=12.8 s

Therefore, the average velocity is

`v=(S)/(t)=(1.46 m)/(12.8 s)=0.11 m/s`

in the positive x-direction.