Answer:

Explanation:
x + y = 12 -------------------------(1)
2x + 5y = 27 --------------------(2)
Multiply (1) by 2
2(x+y) = 12 * 2
2x + 2y = 24 --------------------(3)
Subtract (3) from (2)
2x + 5y - ( 2x + 2y ) = 27 - 24
2x + 5y - 2x - 2y = 3
5y - 2y = 3
3y = 3
Divide 3 to both sides
y = 1
Put y = 1 in (1)
x + 1 = 12
x = 12 - 1
x = 11
So,
x = 11 , y = 1
![\rule[225]{225}{2}](https://img.qammunity.org/2022/formulas/mathematics/high-school/3icqlwn6du2l5ygbr7z2lp6sjjralcpq09.png)
Hope this helped!
~AH1807