1) The distance travelled by the rocket can be found by using the basic relationship between speed (v), time (t) and distance (S):
![v=(S)/(t)](https://img.qammunity.org/2019/formulas/physics/high-school/ig0h9m8v4b4awyr06cyyv68yj2zuldjad5.png)
Rearranging the equation, we can write
![S=vt](https://img.qammunity.org/2019/formulas/physics/high-school/fro6tmi9yo810brq9dubeyq3k8od43ohiw.png)
In this problem, v=14000 m/s and t=150 s, so the distance travelled by the rocket is
![S=vt=(14000 m/s)(150 s)=2.1 \cdot 10^6 m](https://img.qammunity.org/2019/formulas/physics/middle-school/y15ocv6a84h74ru4jbwkgfyghe4kt2xlzo.png)
2) We can solve the second part of the problem by using the same formula we used previously. This time, t=300 s, so we have:
![S=vt=(14000 m/s)(300 s)=4.2 \cdot 10^6 m/s](https://img.qammunity.org/2019/formulas/physics/middle-school/d8ajuio0broi9imdd2s6xqt7l2an8a3jho.png)