Question

A squirrel runs at a steady rate of 0.51 m/s in a circular path around a tree. If the squirrel's centripetal acceleration is 0.43 m/s 2 , what is the radius of the circle?

0.60 m 1.2 m 0.36 m 0.84 m

Answer 1

the image is answer.................

Answer 2

Radius of the circle, r = 0.60 meters.

Explanation:

It is given that,

Speed of the squirrel, v = 0.51 m/s

The centripetal acceleration of the squirrel,
`a=0.43\ m/s^2`

We need to find the radius of the circle. The centripetal acceleration is given by :

`a=(v^2)/(r)`

`r=(v^2)/(a)`

`r=((0.51)^2)/(0.43)`

r = 0.60 m

So, the radius of the circle is 0.60 meters. Hence, this is the required solution.