What value of k makea the equation true (5a^2b^3)(6a^kb)=30a^6b^4

asked Dec 15, 2019 102k views

3 votes

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4 votes

Answer:

k=4

Explanation:

edge2021

Pjohansson answered Dec 18, 2019

6.8k points

0 votes

$(5a^2b^3)(6a^kb)=30a^(2+k)b^4\\\\30a^(2+k)b^4=30a^6b^4\\\Downarrow\\ a^(2+k)=a^6\\ 2+k=6\\ k=4$

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