Answer:
D.
![f(-2)=3](https://img.qammunity.org/2019/formulas/mathematics/high-school/xmmvcey56n7qcfzjiggpdljxwtzfz3bitw.png)
Step by step explanation:
We have been given a piece wise function:
![f{x}=\left\{\begin{matrix}-x^(2); &x< -2 \\3;&-2\leq x< 0\\x+2; & x\geq 0\end{matrix}\right](https://img.qammunity.org/2019/formulas/mathematics/high-school/k3gra42xvwci31sfqqi1ov44aue4gnc7wc.png)
We are asked to find value of f(-2).
In our piece function when we will input values of x less than -2(
) , it will give us output as
![-x^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ymhumxden0poo8huwqy926v0bc4iiewmbx.png)
For values greater than or equal to 0 our function will give output as x+2.
We can see from our piece wise function that when x is greater than or equal to -2 and less than 0 our function gives a constant output, that is 3.
Therefore,
and option D is the correct choice.