Part A:
For a table to be considered a function, every x-value must have one y-value.
Each x-value in this table is unique, and has only one y-value, so this table
does represent a function.Part B:
Plug in 7 for every x in the relation:
![2(7) + 13 = 14 + 13 = 27](https://img.qammunity.org/2019/formulas/mathematics/middle-school/yaw0llgmpip8ot8ohand7shtjb8ycqvrjp.png)
The table's output when x = 7 is 11. Compare the two outputs:
11 < 27
The relation, 2x + 13, has a greater value when x = 7.
Part C:
Set the relation to equal 75:
![2x + 13 = 75](https://img.qammunity.org/2019/formulas/mathematics/middle-school/10dn2fcnjfdspdvjf3yr69pj51udv9eux5.png)
Subtract 13 from both sides:
![2x = 62](https://img.qammunity.org/2019/formulas/mathematics/middle-school/yssurkv5vegdwzomb52qwj82cjx7q91qk7.png)
Divide both sides by 2 to get x by itself:
![\boxed{x = 31}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/f7fre2ot4aj4mhjwz67lm5cyihwsrp56h0.png)
The x value that produces an output of 75 will be
31.