Question

A helium balloon contains 0.40 g of helium. given the molecular weight of helium is 4.0 g/mol, how many moles of helium does it contain?

Answer 1

The helium balloon with 0.40 g of helium contains 0.10 moles of helium when dividing the mass of helium by its molar mass (4.0 g/mol).

Step-by-step explanation:

To determine the number of moles of helium in a helium balloon containing 0.40 g of helium, given the molecular weight of helium is 4.0 g/mol, we use the formula:

n = m / M

Where n is the number of moles, m is the mass of helium, and M is the molar mass of helium.

n = 0.40 g / 4.0 g/mol

The calculation gives us n = 0.10 moles of helium in the balloon.

Answer 2

Answer is 0.10 mol.

Explanation;

n = m/M

Where n is number of moles (mol), m is the mass of substance (g) and M is the molar mass of the substance (g/mol).

n = ?

m = 0.40 g

M = 4.0 g/mol

From substitution,

n = 0.40 g /4.0 g/mol

n = 0.10 mol

Hence, the balloon has 0.10 mol of He.