Question

What is the true solution to 2 ln e^ln5x=2 ln 15

A)x=0
B)x=3
C)x=9
D)x=15
Please Help 15 Points

Answer 1

First you should see that the 2s cancel out. The equation becomes:


`ln( e^(ln(5x)) ) = ln15`

Use the laws of logarithms, knowing that ln(e) = 1.


`ln(5x) = ln(15) \\ 5x = 15 \\ x = 3`

The answer is B.

Hopefully this helps!

Answer 2

x=3

Explanation:

Given in an equation as

`2 ln e^ln5x=2 ln 15`

Divide 2 to get

`ln e^ln5x= ln 15`

Using log rules for exponents we get

ln 5x = ln 15

Cancel ln to get

`5x=15x=3`

Hence solutin is x=3