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Which second degree polynomial function has a leading coefficient of -1 and root 4 with multiplicity 2

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\bf \stackrel{\textit{root of 4}}{x=4\implies x-4=0}\qquad \stackrel{\stackrel{multiplicity}{of~two}}{(x-4)^2}\qquad \implies \stackrel{FOIL}{x^2-8x+16} \\\\\\ \stackrel{\textit{multiplying by -1}}{-1x^2+8x-16}
User Ilya Bibik
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5 votes

Answer:

The polynomial is
-1y^(2)+8y-16

Explanation:

we have to construct a second degree polynomial function has a leading coefficient of -1 that means polynomial having the highest power 2 and having the coefficient of
y^(2) is -1.

One more condition is that having the root 4 with multiplicity 2

Multiplicity means how many times a particular root get when equate to zero or we can say a number is zero for given polynomial function.


-1y^(2)+8y-16

For sol
-1y^(2)+8y-16=0


(y-4)^(2)=0

This implies the above polynomial is of multiplicity 2

User ObiWanKenobi
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