A) you must plug in 50 for variable F and solve for C
C=
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
(50-32)
C=
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
(18)
C= 10
50 degrees fahrenheit is equal to
10 degrees celsius B) you must solve the equation for F
C=
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
(F-32)
C/
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
=F-32
C/
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
+32=F
F= C/
![(5)/(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/y43j9royuingr99vtd1210wwrcsu5ma3o7.png)
+32
dividing by a fraction is the same as multiplying buy its reciprocal so it can also be written as
F=
C +32
now you just plug in 50 for the variable C in the new equation
F=
![(9)/(5)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/zpag3svjpxw5kh0l11nzhcf0hybbeca4pf.png)
(50) +32
F= 90 + 32
F= 122
50 degrees celsius is equal to
122 degrees fahrenheit
hope this helped!