71.0k views
3 votes
What is the mass in grams of a sample of 1.20×1022 exponent atoms of mercury

User ShaunUK
by
7.3k points

1 Answer

3 votes
For this problem, we are going to be using multiplication and cancelling units. We need to first find the molar weight of mercury, found on the periodic table as 200.59g/mol.

So then we set up the equation:


(1.20* 10^(22)atoms )/(1)* (1mole)/(6.022* 10^(23)atoms ) * (200.59gHg)/(1mole)


Then we multiply straight across to find the mass in grams:



(1.20* 10^(22)atomsHg )/(1)* (1 mole)/(6.022* 10^(23)atoms ) * (200.59g)/(1mole) = 3.99g Hg

So now we know that the mass of this sample is 3.99g Hg.
User Veeraraghavan N
by
8.1k points