Question

Identify the vertical asymptote of the function. f(x)=x^2+1/3(x-8) The vertical asymptote is at x =___

Answer 1

A vertical asymptote will occur when the denominator ( 3(x - 8) = zero. That is when x = 8

Answer x = 8

Answer 2

`x =8`

Explanation:

Given is a rational function in x as

`f(x) =(x^2+3)/(3(x-8))`

This function has denominator which has x-8 as a factor.

Hence this becomes undefined when denominator =0

i.e. when
`x-8=0\\x=8`

So vertical asymptote is at
`x =___8____`