Let
x--------> the length of the plot (side along the river)
y--------> the width of the plot
we know that
Area of the plot=x*y------> equation 1
perimeter of the plot=x+2y
perimeter of the plot=450 m
so
x+2y=450-----> 2y=450-x------> divide by 2 both sides
y=225-0.50x-------> equation 2
substitute the equation 2 in equation 1
A=x*[225-0.50x]------> A=225x-0.50x²
using a graph tool
see the attached figure
the vertex is the point (225, 25312.5)
that means for x=225 m the value of the area is a maxim
find the value of y
A=x*y-------> y=A/x-----> y=25312.5/225------> y=112.5 m
the answer part a) is
the length of the plot (side along the river) is 225 m
the width of the plot is 112.5 m
the answer part b) is
the largest area that can be enclosed is 25,312.5 m²