Question

Name the postulate or theorem you can use to prove NPM=OMP

Answer 1

ΔNPM and ΔOMP by SAS postulate

B is correct

Explanation:

In ΔNPM and ΔOMP

NP = OM (Given)

∠NPM = ∠OMP (Given)

PM = MP ( Common )

So, ΔNPM ≅ ΔOMP by SAS property of concurrency.

ΔNPM and ΔOMP are congruent because their two side and angle between them are equal.

Therefore, SAS postulate use here

Hence, ΔNPM and ΔOMP by SAS postulate