Question

Which system of equations could be graphed to solve the equation below?

log(2x+1)=3x-2
A. y1=3x, y2=2x
B. y1=log(2x+1), y2=3x-2
C. y1=log2x+1, y2=3x-2
D. y1=log(2x+1+2), y2=3x

Answer 1

The answer is B

Explanation:

Answer 2

The system of equations are
`y_1=\log(2x+1)` and
`y_2=3x-2`

B is correct.

Explanation:

Given:
`\log(2x+1)=3x-2`

We are given a equation of log and linear. We need to make system of equation.

We will separate left side and right side function.

`\text{Left Side}=y_1`

`\text{Right Side}=y_2`

`y_1=\log(2x+1)`

`y_2=3x-2`

The system of equations are
`y_1=\log(2x+1)` and
`y_2=3x-2`

We get two new function with x and y.

Hence, The system of equations are
`y_1=\log(2x+1)` and
`y_2=3x-2`