Question

The sum of three numbers is 78. The second number is 2 times the third. The third number is 6 more than the first. What are the numbers?

Answer 1

x+y+z=78
y =2z
z=x+6

We can express x and y from 2nd and 3d equations, and substitute their values into the 1st.

y = 2z and x= z-6

x+y+z=78
z-6+2z+z=78
4z -6 =78
4z= 84
z=21

y =2z , y=2*21, y=42

x= z-6, x= 21-6, x=15

Answer: x=15, y=42, z=21.

Check:
15+42+21 = 78
78=78