Question

What is the mass of ammonium nitrate in 250 mL of a 75% by mass solution (density = 1.725 g/mL)?

Answer 1

1) We need to find mass of the solution

m=D*V
D= 1.725 g/mL
V= 250 mL
m=1.725 g/mL*250 mL= 431.25 g

2) 75% = 0.75
0.75*431.25 ≈ 323 g of NH4NO3

Answer 2

Step-by-step explanation:

Density is the mass present in per unit volume.

Mathematically, Density =
`(mass)/(volume)`

Therefore, first calculate the mass of solution as follows.

Density =
`(mass)/(volume)`

1.725 g/mL =
`(mass)/(250 mL)`

mass = 431.25 g

Now, calculate mass of ammonium nitrate as follows.

Percentage by mass =
`\frac{\text{mass of ammonium nitrate}}{\text{mass of solution}} * 100`

75 =
`\frac{\text{mass of ammonium nitrate}}{431.25g} * 100`

Mass of ammonium nitrate = 323.43 g

Thus, we can conclude that mass of ammonium nitrate is 323.43 g.