Question

In 2000, the population of Littletown was 17,000.

Assuming a doubling time of 26 years, predict the population in 2010, rounded to
the nearest thousand

Answer 1

We first must solve for the rate:Rate = 10^[(log[Ending Amount / Beginning Amount] ÷ time)] -1
Rate = 10^[(log(34,000 / 17,000) / 26)] -1Rate = 10^[log(2) / 26] -1Rate = 10^[0.30102999566 / 26] -1Rate = (10^ 0.0115780768) -1
Rate = 1.0270180507-1Rate = .0270180507

Now for the 2010 population:2010 Amount = 2000 Amount × (1 + rate) time
2010 Amount =17,000 * (1.0270180507)^10
2010 Amount =17,000 * 1.3055116977 2010 Amount = 22,194

Source 1728.com/expgrwth.htm