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Please help asap!

if a line crosses the y-axis at (0,1) nd has a slope of 4/5, what is the equation of the line?

A) 4y - 5x = 5
B) y - 4x = 5
C) 5y + 4x = 5
D) 5y - 4x = 5

2 Answers

5 votes

Answer:

Explanation:

Please help asap! if a line crosses the y-axis at (0,1) nd has a slope of 4/5, what-example-1
User Anger
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7.4k points
2 votes
A line has a general equation of

y = mx + b
where b is the y-intercept and slope of m.

Since (0,1) is the value of y when x=0, it is the point of intersection of the line with the y-axis, hence the y-intercept is b=1.

We are given the slope is m=4/5

So the equation of the line is
y=(4/5)x+1
To eliminate fractions (as in the answer choices), we multiply by 5,
5y=4x+5

The only equivalent out of the answer choices is
5y-4x=5 after subtracting 4x from both sides.
User Hannebaumsaway
by
7.9k points

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