2 Answers

Arlette · Answer 1 · 2019-12-12T14:10:41+0000

Arithmetic sequence:
a₁ = 12; a₂ = 14; a₃ = 16; a₄ = 18... a₂₉ = ?

the common difference:
d = a₂ - a₁ = 14 - 12 = 2

29th term:
a₂₉ = a₁ + d(n-1)
= 12 + 2(29-1)
= 12 + 2*28
= 12 + 56
= 68

Answer is A.68

Sabuncu · Answer 2 · 2019-12-16T11:01:50+0000

Hello!

The pattern is add 2. The 1st number is 12.

The 29th term is equal to: (28 × 2) + 12

29 × 2 = 56

Add 12 to 56

56 + 12 = 68

$\framebox{Your answer A. 68}$

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