Question

Please answer these 6 problems. Find the missing side to nearest tenth.

I will mark the answer if all are correct and rounded.

Answer 1

You should be applying the Pythagorean Theorem to all 8 of these problems.

In the first problem, 3^2 + 4^2 = h^2, where h is the length of the hypotenuse.

Then 9+16 = h^2, and h = +sqrt(25) = +5 (answer).

Answer 2

Since these are right triangles you can use the pythagorean theorem
a² + b² = c²
a = one leg of the triangle
b = the other leg of the triangle
c = the hypotenuse

1. 4² + 3² = c²
16 + 9 = c²
25 = c²
√25 = √c²
5 = c
c = 5cm

2. 5² + 12² = c²
25 + 144 = c²
169 = c²
√169 = √c²
13 = c
c = 13in

4. 7² + 9² = c²
49 + 81 = c²
130 = c²
√130 = √c²
11.4 = c
c = 11.4cm

5. a² + 10² = 15²
a² + 100 = 225
a² = 125
√a² = √125
a = 11.2ft