Hey there!
Let
x equal the smaller positive number and let y equal the greater number.
We can represent the product of the two numbers equaling 112 with this equation:
xy=112
We can represent the larger number being greater than the smaller number by 6 with this equation:
y=x+6
Because you know that the value of y is equal to x+6, you can substitute x=6 for y in the first equation:
y=x+6
xy=112
x(x+6)=112
Now, simplify and set your equation to 0 so the equation can be solved as a quadratic:
x(x+6)=112
![x^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/x18wowxes8du7ezs6fltwoqbv6i8lovbjg.png)
+6x=112
![x^(2)](https://img.qammunity.org/2019/formulas/mathematics/high-school/x18wowxes8du7ezs6fltwoqbv6i8lovbjg.png)
+6x-112=0
Use the quadratic formula to solve for the values of x:
![\frac{-6+- \sqrt{ 6^(2) -4(-112)(1)} }{2}](https://img.qammunity.org/2019/formulas/mathematics/middle-school/7h8qv6d93349jmauwqoaqs3gpggaej769w.png)
![(-6+- √(36+448) )/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/rwnpzv5ajc77lr30lgtg9k7hxp4dej07yt.png)
![(-6+- √(484) )/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/pbcd0ctdhk02ovx4t1y16fc3pb2v36cql9.png)
![(-6+-22)/(2)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/y9462l708t2y3vjla4ji0v5ibyz9kbz113.png)
x=8 or -14
Because you want a positive solution, you would use x=8 as one of your final solutions.
Now, you need to find the other number.
To do this, plug x=8 into y=x+6.
y=8+6
y=14
Therefore, your final answers would be 8 and 14.
Hope this helps!