Our P = 100, r = .08, n = 1 (annually means once a year), and t = 15. Filling in accordingly, we have
![A(t)=100(1+ (.08)/(1))^((1)(15))](https://img.qammunity.org/2019/formulas/mathematics/high-school/z04bb83njn7tqrqed5h7gv1l74mixoa54l.png)
. Simplifying a bit gives us
![A(t)=100(1+.08)^(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/ciz3g9t9qr8mxvdriafiozejjba3hd2w3l.png)
and
![A(t)=100(1.08)^(15)](https://img.qammunity.org/2019/formulas/mathematics/high-school/2a2q08eu22d31raim6zhjjput0h2qphihl.png)
. Raising that number inside the parenthesis to the 15th power gives us
![A(t)=100(3.172169114)](https://img.qammunity.org/2019/formulas/mathematics/high-school/v7m115yc7enx4fb518jkum9z7akkjzdfh9.png)
. Multiplying to finish means that A(t) = $317.22