To begin to solve this problem, we must first note that when you are doing n + (-z), it is equal to n - z. Now, knowing this, we need to begin to find the LCD of 8 and 2. The LCD of 8 and 2 is 8, so now we need to turn -
![(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/q5zg49mbtfrwobmmahi676fbgez56hhab0.png)
into something over 8. -
![(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/q5zg49mbtfrwobmmahi676fbgez56hhab0.png)
becomes -
![(4)/(8)](https://img.qammunity.org/2019/formulas/mathematics/high-school/eusef271rqjv0xnza3mle64uzxqmnd4cgg.png)
. Now, we can subtract the numerators over a common denominator. -7 - 4 is -11, so -
![(7)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/heyfbusvelejms7vfs1jao2x26yjrbbp8v.png)
+ (-
![(1)/(2)](https://img.qammunity.org/2019/formulas/mathematics/college/q5zg49mbtfrwobmmahi676fbgez56hhab0.png)
) is -
![(11)/(8)](https://img.qammunity.org/2019/formulas/mathematics/middle-school/5slg0bdwqorrhv6n5pxe74fz4e6fyhhdjl.png)
.